(1/64x^2)-(1/48y^2)=0

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Solution for (1/64x^2)-(1/48y^2)=0 equation: 


x in (-oo:+oo)

(1/64)*x^2-((1/48)*y^2) = 0

(1/64)*x^2+(-1/48)*y^2 = 0

1/64*x^2 = -(-1/48*y^2) // : 1/64

x^2 = 4/3*y^2

x^2 = 4/3*y^2 // ^ 1/2

abs(x) = (4/3)^(1/2)*y

x = (4/3)^(1/2)*y or x = -((4/3)^(1/2)*y)

x in { (4/3)^(1/2)*y, -((4/3)^(1/2)*y) }

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